The volume of hydrogen formed by the action of an excess of hydrochloric acid on 130 grams of zinc is equal to.

Zinc reacts with hydrochloric acid to release hydrogen gas and form zinc chloride.

Zn + 2HCl = ZnCl2 + H2;

1 mole of metal reacts with 2 moles of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the available chemical amount of zinc. To do this, divide the weight of pure metal by the weight of 1 mole of metallic zinc.

M Zn = 65 grams / mol; N Zn = 130/65 = 2 mol;

The same amount of hydrogen and zinc chloride salt will be synthesized.

Let’s calculate the volume of hydrogen. To do this, multiply the amount of substance by the volume of 1 mole of gas, which is 22.4 liters.

N H2 = 2 mol; V H2 = 2 x 22.4 = 44.8 liters;