The volume of hydrogen formed by the interaction of hydrochloric acid with 0.2 mol of magnesium is …

1. We write down the reaction equation:

2HCl + Mg = MgCl2 + H2 ↑;

2.the coefficients before magnesium and hydrogen in the equation are equal, therefore, the chemical quantities of these substances will be equal:

n (H2) = n (Mg) = 0.2 mol;

3.Calculate the volume of hydrogen:

V (H2) = n (H2) * Vm = 0.2 * 22.4 = 4.48 dm3.

Answer: 4.48 dm3.



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