The volume of hydrogen released during the interaction of 3.75 mol of zinc with an excess

The volume of hydrogen released during the interaction of 3.75 mol of zinc with an excess of a dilute solution of sulfuric acid is equal to

During the course of this reaction, the amount of synthesized hydrogen will be equal to the amount of metal dissolved in the acid.

Zn + H2SO4 → ZnSO4 + H2;

The amount of zinc according to the condition of the problem is 3.75 mol.

With this amount of zinc and a sufficient amount of acid, it is possible to obtain the same 3.75 moles of hydrogen.

Let us calculate the volume of synthesized 3.75 mol of hydrogen.

V H2 = 22.4 x 3.75 = 84 liters;