The volume of hydrogen released when zinc interacts with 490 g. 10% sulfuric acid solution

Zinc reacts violently with sulfuric acid to release hydrogen gas. At the same time, zinc sulfate (zinc sulfate) is synthesized. This reaction is described by the following equation:

Zn + H2SO4 = ZnSO4 + H2;

The metal reacts with acid in equivalent molar amounts. At the same time, the same amounts of zinc sulfate and hydrogen are synthesized.

Let’s calculate the available chemical amount of sulfuric acid. To do this, divide its weight by the weight of 1 mole of acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; N H2SO4 = 490 x 0.1 / 98 = 0.5 mol;

The same amount of hydrogen and zinc sulfate will be synthesized.

Let’s calculate the volume of the synthesized amount of hydrogen. To do this, multiply its amount by the volume of 1 mole of gas (22.4 liters).

N H2 = 0.5 mol; V H2 = 0.5 x 22.4 = 11.2 liters;