The volume of hydrogen required to react with 160 g of copper oxide (2-valent).

CuO + H2 = Cu + H2O
According to the periodic table, we determine the molar mass of copper oxide: M = 63.5 + 16 = 79.5 g / mol.
The amount of copper oxide: n = m / M = 160 g / 79.5 g / mol = 2.01 mol.
By reaction with 1 mol of copper oxide, 1 mol of hydrogen reacts, which means n (CuO) = n (H2) = 2.01 mol.
The volume of hydrogen: V = n * Vm = 2.01 mol * 22.4 l / mol = 45.02 l. Vm – molar volume, constant for all gases at normal conditions.
Answer: 45.02 liters.