The volume of hydrogen sulfide, which is required to prepare 136 g of a 5% solution of hydrogen sulfide acid is?

First, let’s find the mass of pure hydrogen sulfide in the solution:
0.05 (5%) * 136 g = 6.8 g
Now we find the amount of hydrogen sulfide m / M = 6.8 (g) / 34 (g / mol) = 0.2 (mol).
Now we find the volume 0.2 (mol) * 22.4 (l / mol) = 4.48 (l)



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