The volume of hydrogen that is released when aluminum interacts with 294 g of a 25% sulfuric acid solution.

Metallic aluminum interacts with sulfuric acid. In this case, aluminum sulfate is synthesized and bubbles of hydrogen gas are released. The reaction is described by the following equation.

2Al + 3H2SO4 = Al2 (SO4) 3 + 3 H2;

Let’s determine the chemical amount of sulfuric acid. For this purpose, we divide its weight by the molar weight of the substance.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 294 x 0.25 / 98 = 0.75 mol;

The sulfuric acid will react to produce the same amount of hydrogen gas.

Let’s find its volume.

To do this, multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 0.75 x 22.4 = 16.8 liters;