The volume of hydrogen that will be released during the interaction of 460 g with sodium with water.

1. The interaction of sodium with water proceeds according to the reaction equation:

2Na + 2H2O = 2NaOH + H2 ↑;

2.Calculate the chemical amount of sodium:

n (Na) = m (Na): M (Na) = 460: 23 = 20 mol;

3. according to the reaction equation from 2 mol of sodium, 1 mol of hydrogen is obtained, we determine the amount of formed hydrogen:

n (H2) = n (Na): 2 = 20: 2 = 10 mol;

4.calculate the volume of hydrogen:

V (H2) = n (H2) * Vm = 10 * 22.4 = 224 HP

Answer: 224 l.