The volume of hydrogen that will be released during the interaction of magnesium weighing 16 g

The volume of hydrogen that will be released during the interaction of magnesium weighing 16 g with an excess of formic acid is equal to ..

Metallic magnesium dissolves in formic acid solution. The chemical reaction proceeds according to the following equation:

Mg + 2HCOOH = Mg (HCOO) 2 + H2 ↑;

Find the molar amount of magnesium.

For this purpose, we divide its mass by the weight of 1 mole of metallic magnesium.

M Mg = 24 grams / mol;

N Mg = 16/24 = 0.666 mol;

The same amount of hydrogen gas will be produced.

Let’s calculate the volume of hydrogen.

To do this, multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V H2 = 0.666 x 22.4 = 14.93 liters;