The volume of lead shot is 0.2 cm3, the density of lead is 11.3 g / cm3. Determine its mass.

These tasks: V (the volume of the taken lead fraction) = 0.2 cm3 (in the SI system V = 0.2 * 10-6 m3).

Reference values: according to the condition ρс (lead density) = 11.3 g / cm3 (in SI system ρс = 11300 kg / m3).

To determine the mass of the taken lead fraction, we use the formula: m = ρс * V.

Let’s calculate: m = 11300 * 0.2 * 10-6 = 0.00226 kg (2.26 g).

Answer: The taken lead shot has a mass of 2.26 g.



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