The volume of one ball is 64 times the volume of the second. How many times is the surface area

The volume of one ball is 64 times the volume of the second. How many times is the surface area of the first ball more than the surface area of the second?

The volume of a sphere is directly proportional to the cube of its radius, and the surface area is proportional to the square of its radius.

Comparing the first and second balls, let us first compare their radii.

Since the volume of the first ball is 64 times the volume of the second ball, the radius of the first ball is √64 = 4 times larger than the radius of the second ball.

Therefore, the surface area of the first ball will be in
4 ^ 2 = 16 times the surface area of the second ball.

Answer: 16 times.



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