The volume of oxygen required for complete combustion of 4.6 g of dimethyl ether is

Let us carry out the solution, according to the condition of the problem, we compose the equation:
CH3 – O – CH3 + 3O2 = 2CO2 + 3H2O – dimethyl ether combustion reaction, carbon dioxide and water are released;
Let’s calculate the molar masses:
M (C2H6O) = 46 g / mol;
M (O2) = 32 g / mol.
Let’s calculate the number of moles of ether, if the mass is known:
Y (C2H6O) = m / M = 4.6 / 46 = 0.1 mol.
Let’s make the proportion:
0.1 mol (C2H6O) – X mol (O2);
-1 mol                     -3 mol from here, X mol (O2) = 0.1 * 3/1 = 0.3 mol.
We find the volume of oxygen:
V (O2) = 0.3 * 22.4 = 6.72 liters.
Answer: for the combustion reaction, O2 in a volume of 6.72 liters is required.