The volume of oxygen required for the complete oxidation of 22.4 liters of ammonia to form nitrogen.

Let’s write down the reaction scheme and arrange the coefficients using the electronic balance method, since the reaction is redox:

4NH₃ + 3O₂ = 2N₂ + 6H₂O

2N^_(-3) – 2 * 3e = N₂

O₂⁽⁰⁾ + 2 * 2e = 2O^_(-2)

It can be seen from the reaction equation that 4 volumes of ammonia require 3 volumes of oxygen (this reasoning is applicable only for reactions occurring in the gas phase), that is, 4V (NH3) = 3V (O2), then V (O2) = 4V (NH3) / 3 = 4 * 22.4 / 3 = 29.87 l