# The volume of oxygen required for the complete oxidation of 22.4 liters of ammonia with the formation of nitrogen …

The reaction of non-catalytic oxidation of ammonia with oxygen is described by the following chemical equation:

4NH3 + 3O2 = 2N2 + 6H20;

Let’s determine the chemical amount of a substance in 22.4 liters of ammonia.

To do this, we divide its volume by the volume of 1 mole of gas (assuming a volume of 22.4 liters).

N NH3 = 22.4 / 22.4 = 1 mol;

To oxidize such an amount of a substance, it is necessary to take (in accordance with the coefficients of the chemical equation) 1 x 3/4 = 0.75 mol of oxygen.

Let’s find the volume of gaseous oxygen.

To do this, multiply its amount by the volume of 1 mole of gas (equal to 22.4 liters).

V O2 = 0.75 x 22.4 = 16.8 liters;

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