The volume of the pool is 800 m3, the sides of the base are equal to 40 and 10 m.

The volume of the pool is 800 m3, the sides of the base are equal to 40 and 10 m. How many square meters of tiles did you need to cover the pool?

The pool consists of a base (bottom) and four more sides, the lengths of which are equal to the length of each side of the base. We will assume that the pool is rectangular and do not take into account the lining of the curb on the way to it (that is, at a minimum).

Then the height (depth of the pool) is determined from the volume as follows:

800: (40 * 10) = 800: 400 = 2 (m).

Bottom area:

40 * 10 = 400 (m²).

Long side area (there are only 2 of them):

40 * 2 = 80 (m²).

The area is short (there are also 2 of them):

10 * 2 = 20 (m²).

Total surface area:

(20 + 80) * 2 + 400 = 100 * 2 + 400 = 600 (m²).



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