# The volume of the rectangular parallelepiped is 84 cm3. This parallelepiped was divided into two parts

**The volume of the rectangular parallelepiped is 84 cm3. This parallelepiped was divided into two parts. Find the volume of each part if: a) the volume of one part is 6 times higher than the volume of the other. b) the volume of one part is 40 cm cubed more than the volume of the other.**

a) Let’s represent the volume of one part as x, and the volume of the second part as 6 * x. The volume of the whole parallelepiped is 84 cm³. Let’s compose and solve the equation.

x + 6 * x = 84 cm³.

7 * x = 84 cm³.

x = 12 cm³

Let’s find the volume of the second part: 84 cm³ – 12 cm³ = 72 cm³.

b) If the volume of one part is 40 cm³ larger than the other, then we make the following equation.

x + 40 cm³ + x = 84 cm³.

2 * x = 44 cm³.

x = 22 cm³.

The volume of the second part is equal to: 22 cm³ + 40 cm³ = 62 cm³.

Answer: the volumes of the parts are equal to a) 12 cm³ and 72 cm³, b) 22 cm³ and 62 cm³.