The volume of the steel bar is 2 dm³. What is the buoyancy force on the bar when it is immersed in water?

Given:

V = 2 cubic decimeters – the volume of the steel bar;

ro = 1000 kilograms / cubic meter – density of water;

g = 10 Newton / kilogram – acceleration of gravity.

It is required to determine A (Newton) – the buoyancy force acting on the bar when immersed in water.

Let’s convert the units of measurement of volume from cubic decimeters to cubic meters:

V = 2 dm3 = 2 * 10-3 = 2/1000 = 0.002 cubic meters.

Then the buoyant (Archimedean) force will be equal to:

A = ro * V * g = 1000 * 0.002 * 10 = 2 * 10 = 20 Newtons.

Answer: the buoyancy force will be equal to 20 Newtons.