The volume of water is 0.25 liters and a temperature of 20 degrees is heated to a boil to determine

The volume of water is 0.25 liters and a temperature of 20 degrees is heated to a boil to determine the amount of heat passed to heat the water.

The boiling point of water is 100 degrees Celsius
0.25 l = 2.5 * 10 ^ -4 cubic meters
Q = cmd (t) (d-delta, c-specific heat) = cpvdt (p-density (for water 1000 kg per cubic meter), v-volume) = 4200 * 1000 * 2.5 * 10 ^ -4 * (100-20) = 84 kJ



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