The water pressure in the cylinder of the injection pump is 1200 kPa. What is the work equal to when the piston

The water pressure in the cylinder of the injection pump is 1200 kPa. What is the work equal to when the piston moves with an area of 400 cm2 at a distance of 50 cm

To find out the work done while moving the specified piston, we apply the formula: A = F * L = P * S * L.
Data: P – water pressure in the considered cylinder (P = 1200 kPa = 1.2 * 106 Pa); S is the area of the indicated piston (S = 400 cm2, in the SI system S = 0.04 m2), L is the movement of the piston (L = 50 cm, in the SI system L = 0.5 m).
Let’s perform the calculation: A = P * S * L = 1.2 * 10 ^ 6 * 0.04 * 0.5 = 24 * 10 ^ 3 J.
Answer: When the indicated piston was moved, a work of 24 kJ was performed.