The water pump can generate a pressure of 220 kPa. how high can he blow the water?

To find out the maximum height to which the specified pump can supply water (fresh), we use the formula: Рhydr = ρпв * g * hmax, whence we express: hmax = Рhydr / (ρпв * g).

Const: ρпв – fresh water density (ρпв = 10 ^ 3 kg / m3); g – acceleration due to gravity (g ≈ 9.81 m / s2).

Data: Phydr – the hydrostatic pressure created by the indicated pump (Phydr = 220 kPa = 22 * 10 ^ 4 Pa).

Let’s perform the calculation: hmax = Рhydr / (ρпв * g) = 22 * 10 ^ 4 / (10 ^ 3 * 9.81) ≈ 22.426 m.

Answer: The maximum pump head for fresh water is 22.426 m.