The water pump delivers 300 liters of water per minute to a height of 20 m.

| August 9, 2021 | education

The water pump delivers 300 liters of water per minute to a height of 20 m. Determine the pump motor power if its efficiency is 80%.

To find the power value of the engine of the specified water pump, we apply the formula: η = Npol / Nd = (A / t) / Nd = ρw * V * g * h / (t * Nd), whence we express: Nd = ρw * V * g * h / (η * t).

Data: ρw is the density of the supplied water (ρw = 1000 kg / m3); V is the volume of water (V = 300 l = 0.3 m3); g – acceleration due to gravity (g ≈ 10 m / s2); h – delivery height (h = 20 m); η – efficiency of the specified water pump (η = 80% = 0.8); t – elapsed time (t = 1 min = 60 s).

Calculation: Nd = ρw * V * g * h / (η * t) = 1000 * 0.3 * 10 * 20 / (0.8 * 60) = 1.25 * 10 ^ 3 W.

Answer: The engine power of the specified water pump is 1.25 kW.



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