The water supply pressure tank is located at a height of 8 m and holds 95 m3 of water. Calculate the work done by the pump

The water supply pressure tank is located at a height of 8 m and holds 95 m3 of water. Calculate the work done by the pump when filling this tank if the water is supplied from a well 12 m deep?

Given:

h1 = 8 meters – the height of the water tower;

V = 95 m3 (cubic meters) – the volume that contains the capacity of the tower;

ro = 1000 kg / m3 (cubic meters) – density of water (clean);

h2 = 12 meters – the depth of the well from which the water is supplied;

g = 10 Newton / kilogram – acceleration due to gravity (rounded off value).

It is required to determine A (Joule) – what kind of work is done by the pump when the water rises into the tank of the water tower.

Let’s find the mass of water:

m = V * ro = 95 * 1000 = 95000 kilograms.

To raise the water, you need to apply force:

F = m * g = 95000 * 10 = 950000 Newton.

The total lifting height will be equal to:

h = h1 + h2 = 8 + 12 = 20 meters.

Then the work will be equal to:

A = F * h = 950,000 * 20 = 19,000,000 Joules = 95 MJ.

Answer: The work done by the pump is 95 MJ.



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