The wavelength in the air for the lowest male voice reaches 4.25 m. Find the frequency of vibration of the vocal cords of such a person?
Task data: λ (wavelength in air for the lowest male voice) = 4.25 m.
Reference data: υ (speed of propagation of a sound wave in air) = 331 m / s.
The frequency of vibrations of the vocal cords of the person in question is calculated by the formula: ν = υ / λ.
Let’s make the calculation: ν = 331 / 4.25 = 77.88 Hz.
Answer: The frequency of vibrations of the vocal cords of the person in question is 77.88 Hz.
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