The wavelength of some rays in water is 435 nm. What is the wavelength of these rays in the air?

| September 25, 2021 | education

The wavelength of some rays in water is 435 nm. What is the wavelength of these rays in the air? The absolute refractive index of water is 1.3.

λ2 = 435 nm = 435 * 10 ^ -9 m.
n = 1.3.
λ1 -?
The absolute refractive index of a substance n is determined by the formula: n = V1 / V2, where V1 is the speed of wave propagation in the first medium, V2 is the speed of wave propagation in the second medium.
When passing from one medium to another, the wavelength λ and the propagation velocity V change, the frequency of the wave v does not change.
The speed of propagation of the wave V is determined by the formula: V = λ * v.
V1 = λ1 * v.
V2 = λ2 * v.
n = λ1 * v / λ2 * v = λ1 / λ2.
λ1 = n * λ2.
λ1 = 1.3 * 435 * 10 ^ -9 m = 565.5 * 10 ^ -9 m.
Answer: the wavelength in the air is λ1 = 565.5 * 10 ^ -9 m.



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