The weight of the bar in the air is 10 H, and when it is lowered into gasoline, its weight becomes 4 H.

The weight of the bar in the air is 10 H, and when it is lowered into gasoline, its weight becomes 4 H. What is the volume of the bar if the density of gasoline is 700 kg / m3.

Initial data: P1 (weight of the taken bar in the air) = 10 N; P2 (weight of the bar when lowered into gasoline) = 4 N.

Reference data: g (acceleration due to gravity) ≈ 10 m / s2; by condition ρb (gasoline density) = 700 kg / m3.

1) Determine the buoyancy force: Fa = P1 – P2 = 10 – 4 = 6 N.

2) Calculate the volume of the bar: V = Fa / (ρb * g) = 6 / (700 * 10) = 8.57 * 10-4 m3 (857 cm3).

Answer: The volume of the taken bar is 857 cm3.