The weight of the concrete beam is 8.8 KN, the volume is 0.4m 3. What force must be applied to keep it in the water?
| June 10, 2021 | education
Data: P (weight of a concrete beam) = 8.8 kN = 8.8 * 10 ^ 3 N; V (beam volume) = 0.4 m3; ρw (density of water in which the beam is immersed) = 1000 kg / m3; g (acceleration due to gravity) = 9.81 m / s2.
The force for holding the beam: F = P – Fa = P – ρw * g * V = 8.8 * 10 ^ 3 – 1000 * 9.81 * 0.4 = 4876 N.
Answer: A force of 4876 N is required to be applied to the beam.
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