The weight of the copper ball lying on the surface is 17.8 kN. Determine the volume of this ball.
| December 7, 2020 | education
The weight of the ball lying on the surface:
P = Ftyazh = mg, whence m = P / g = 1780 kg.
Ball volume: V = m / p, where p is the density of copper, p = 8.93kg / m ^ 3.
Then V = 1780 / 8.93 = 199.3 m ^ 3.
Answer: 199.3 m ^ 3.
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