The weight of the movable block is 10 N. If a force of 105 N is applied to the free end of the rope

The weight of the movable block is 10 N. If a force of 105 N is applied to the free end of the rope, then with the help of this block it is possible to lift the load with what mass.

To determine the mass of the load lifted using the indicated movable block, we use the formula: F = P / 2 = (Pb + m * g) / 2, whence we express: m * g = 2F – Pb and m = (2F – Pb) / g.

Constants and variables: F – applied force (F = 105 N); Pb – own weight of the block (Pb = 10 N); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: m = (2F – Pb) / g = (2 * 105 – 10) / 10 = 20 kg.

Answer: You can lift a load weighing 20 kg.