The weight of the movable block is 20N. If a force of 210N is applied to the free end of the rope

The weight of the movable block is 20N. If a force of 210N is applied to the free end of the rope, then with the help of this block you can lift a load with a mass

Initial data: Pb (weight of the movable block) = 20 N; F (force applied to the free end of the rope) = 210 N.

Reference data: g (acceleration due to gravity) ≈ 10 m / s2.

1) The total weight that can be lifted with the movable unit (the movable unit gives a 2-fold increase in strength): P = 2F = 2 * 210 = 420 N.

2) Weight of the lifted load: Pg = P – Pb = 420 – 20 = 400 N.

3) Mass of the lifted load: m = Pg / g = 400/10 = 40 kg.

Answer: You can lift a load weighing 40 kilograms.