The weight of the resting homogeneous marble column is P = 166.4. Determine the area of the column if its height

The weight of the resting homogeneous marble column is P = 166.4. Determine the area of the column if its height is h = 6.4 and the density of marble is p = 2600 kg / m3. coefficient g = 10H / kg

Marble Column Weight:
P = m * g, where P is the weight of the column (P = 166.4 kN = 166400 N), m is the mass of the marble column, g is the acceleration of gravity (g = 10 N / kg).
Column mass:
m = ρ * V, ρ is the density of the marble (ρ = 2600 kg / m3), V is the volume of the column (V = S * h, where S is the cross-sectional area, h is the height (h = 6.4 m)).
Let’s calculate the cross-sectional area:
P = ρ * S * h * g.
S = P / (ρ * h * g) = 166400 / (2600 * 6.4 * 10) = 1 m2.
Answer: The cross-sectional area is 1 m2.