The weight of the silver ball is 10.5 kg. What is the volume of the cavity in this ball, if the volume of the ball is 10 dm3.
| July 15, 2021 | education
Initial data: m (weight of the silver ball) = 10.5 kg; V (volume of the silver ball) = 10 dm ^ 3.
Reference data: ρ (density of silver) = 10500 kg / m ^ 3.
1) Determine the volume of silver in the ball: V1 = m / ρ = 10.5 / 10500 = 0.001 m ^ 3 = 1 dm ^ 3.
2) Calculate the volume of the cavity in the silver ball: V2 = V – V1 = 10 – 1 = 9 dm ^ 3.
Answer: The volume of the cavity in the silver ball is 9 dm ^ 3.
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