The weightlifter lifted a barbell weighing 125 kg to a height of 70 cm in 0.3 seconds.

The weightlifter lifted a barbell weighing 125 kg to a height of 70 cm in 0.3 seconds. What average power did the athlete develop while doing this?

To find out the average power that the weightlifter in question should have developed, we apply the formula: Nsh = ΔEp / t = m * g * Δh / t.

Const: q – acceleration due to gravity (q = 9.81 m / s2).

Data: m – weight of the bar (m = 125 kg); Δh – change in the height of the rod (Δh = 70 cm, in SI Δh = 0.7 m); t is the duration of the rise (t = 0.3 s).

Calculation: Nsh = m * g * Δh / t = 125 * 9.81 * 0.7 / 0.3 = 2861.25 W ≈ 2.9 kW.

Answer: The weightlifter had to develop a power of 2.9 kW.