The width of a rectangle is 2 times less than its length. Find the perimeter and area of the rectangle if its length is 12 cm.

First of all, we will find the width of the rectangle, knowing that it is 2 times less than its length, equal to 12 cm:

12: 2 = 6 cm.

The perimeter is the sum of all sides. Provided that the opposite dimensions of this figure are equal, we calculate it using the formula:

P = 2a + 2b = 2 * 12 + 2 * 6 = 24 + 12 = 36 cm.

The area corresponds to:

S = a * b = 12 * 6 = 72 cm².