# The width of a rectangular parallelepiped is 2.5 times longer than its height and 3.5 times shorter than its length.

The width of a rectangular parallelepiped is 2.5 times longer than its height and 3.5 times shorter than its length. The sum of the lengths of the edges of a parallelepiped is 1m96cm. Find its height, width and length in centimeters. Using the equation.

1) By the condition of the problem, the width of the rectangular parallelepiped is 2.5 times longer than its height. Thus, let the width of the parallelepiped be x cm, then the height (x / 2.5 = 0.4x). And the length, given that it is 3.5 times the width, is 3.5x.

2) The sum of the lengths of all edges of a rectangular parallelepiped can be found using the following formula: 4 * (a + b + c). According to the condition of the problem, it is equal to 1 m. 96 cm. Let’s translate into centimeters: 1 m. 96 cm = 196 cm.

3) Equation: 4 * (x + 0.4x + 3.5x) = 196. Solve. Divide both sides of the equation by 4. We get: x + 0.4x + 3.5x = 49. We give similar ones: 4.9x = 49; x = 10 cm – width.

4) Height: 10 / 2.5 = 4 cm.

5) Length: 10 * 3.5 = 35 cm.

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