# The width of a rectangular parallelepiped is 2.5 times longer than its height and 3.5 times shorter than its length.

**The width of a rectangular parallelepiped is 2.5 times longer than its height and 3.5 times shorter than its length. The sum of the lengths of the edges of a parallelepiped is 1m96cm. Find its height, width and length in centimeters. Using the equation.**

1) By the condition of the problem, the width of the rectangular parallelepiped is 2.5 times longer than its height. Thus, let the width of the parallelepiped be x cm, then the height (x / 2.5 = 0.4x). And the length, given that it is 3.5 times the width, is 3.5x.

2) The sum of the lengths of all edges of a rectangular parallelepiped can be found using the following formula: 4 * (a + b + c). According to the condition of the problem, it is equal to 1 m. 96 cm. Let’s translate into centimeters: 1 m. 96 cm = 196 cm.

3) Equation: 4 * (x + 0.4x + 3.5x) = 196. Solve. Divide both sides of the equation by 4. We get: x + 0.4x + 3.5x = 49. We give similar ones: 4.9x = 49; x = 10 cm – width.

4) Height: 10 / 2.5 = 4 cm.

5) Length: 10 * 3.5 = 35 cm.