The width of the first section is 4 m of the second 3 m. What is the area of the first section, if their length is the same

The width of the first section is 4 m of the second 3 m. What is the area of the first section, if their length is the same, and the area of the second is 36 m2. How many meters is the perimeter of one section larger than the perimeter of another section?

To solve this problem, recall the formula for the area of a rectangle. The area of the rectangle is equal to the product of the length and the width. S = a * b, where a is the length and b is the width. The perimeter of a rectangle is the sum of the lengths of all its sides. Since in a rectangle the opposite sides are equal, then P = 2 * (a + b), where a is the length, b is the width. Let’s calculate the length of the second section.

a = 36/3 = 12 cm.

Let’s calculate what the perimeter of the first and second sections is equal to.

P = 2 * (12 + 4) = 2 * 16 = 32 centimeters.

P1 = 2 * (12 + 3) = 2 * 15 = 30 centimeters.

32 – 30 = 2 cm.

Answer: 2 cm.



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