The width of the rectangle is 14 cm, and the length is 7 cm longer. Find the perimeter of the rectangle.

Let’s find the length of the triangle:

14 + 7 = 21 (cm).

The perimeter is the sum of the lengths of all sides. Therefore, the perimeter of the rectangle is: 2a + 2b, where a is its length, b is its width. Find the perimeter:

2 * 21 + 2 * 14 = 42 + 28 = 70 (cm).

Now let’s translate the perimeter into decimeters. To do this, divide it by 10 (since 1 dm = 10 cm):

70/10 = 7 (dm).

Answer: 7 dm.



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