The width of the rectangle is 15 cm less than its length. If the width of this rectangle is increased

The width of the rectangle is 15 cm less than its length. If the width of this rectangle is increased by 8 m, and the length is reduced by 6 m, then its area will increase by 80 m3. Find the area of a given rectangle

1. Let X be the width of the rectangle.

It is known that it is 15 m less than its length.

Then the length can be written (X + 15) m.

2. If the width of the figure is increased by 8 meters, it will be equal to (X + 8) m.

If at the same time the length is reduced by 6 m, it will be written as (X + 15 – 6) = (X + 9) m.

3. As a result, the area of the new figure is 80 m2 higher than that of the original one.

(X + 8) * (X + 9) – X * (X + 15) = 80.

X * X + 8 * X + 9 * X + 72 – X * X – 15 * X = 80.

17 * X – 15 * X = 80 – 72.

2 * X = 8.

X = 4 – width, 4 + 15 = 19 – length.

4 * 19 = 76 m2 – the required area.

Answer: the area of the rectangle is 76 m2.