The width of the rectangle is 15 dm, its length is 80 dm, which is greater than the perimeter of this rectangle.
| September 5, 2021 | education
From the condition, we know that the width of the rectangle is 15 dm, and its length is 80 dm greater than its width. In order to find the perimeter of a rectangle, we need to know the lengths of its sides.
Let’s find the length of the rectangle, since we know that the width is 80 inches wider than the width:
15 dm + 80 dm = 95 dm length of the rectangle.
The perimeter of a rectangle is equal to the sum of the lengths of all its sides.
P = 2 (a + b), where a and b are the length and width of the rectangle.
P = 2 (15 + 95) = 2 * 110 = 220 dm perimeter of the rectangle.
Answer: 220 dm.
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