The width of the rectangle is 2 times less than the length. Find the area of a rectangle if its perimeter is 120 m.

1. According to the condition of this problem, the width of the rectangle is 2 times less than the length.

2. So, if the width is taken as X meters, then the length is 2X meters.

3. If the perimeter of the rectangle is 120 meters, then X + X + 2X + 2X = 6X = 120.

4. So X = 120: 6 = 20, that is, the width is 20 m.

5. Therefore, 2X = 2 * 20 = 40, that is, the length is 40 m.

6. The area of a rectangle is equal to the product of length and width, that is, 20 * 40 = 800 m2.