The width of the rectangle is 3.2 times less than the length, and the perimeter is 105 meters.

The width of the rectangle is 3.2 times less than the length, and the perimeter is 105 meters. Find the perimeter and area of a square with a side equal to the width of this rectangle.

To solve this problem, remember that the perimeter of a rectangle is the sum of the lengths of all its sides. Since in a rectangle the opposite sides are equal, then P = 2 * (a + b), where a is the length, b is the width. Let the width be x meters, and the length – 3.2 x m. Knowing that the perimeter is 105 meters, we will compose an equation.
2 * (x + 3.2x) = 105;
2 * 4.2x = 105;
8.4x = 105;
x = 105 / 8.4;
x = 12.5 meters.
the perimeter of a square is equal to the sum of the lengths of all its four sides. Since all sides of a square are equal, its perimeter is P = 4a, where a is its side. The area of ​​a square is equal to the square of its side. S = a ^ 2. Knowing that the side is 12.5 meters, we calculate the area and perimeter.
S = 12.5 * 12.5 = 156.25 m ^ 2.
P = 4 * 12.5 = 50 m.
Answer: 50 m, 25 m ^ 2.