The width of the rectangle is 3 cm less than the length, and the area is 70 cm2

The width of the rectangle is 3 cm less than the length, and the area is 70 cm2. Find the lengths of the sides of the rectangle.

Width (a) -? cm, 3 cm less than the length;

Length (b) -? cm;

Area (Sp.) – 70 cm ^ 2.

The area of the rectangle is found by the formula:

Sp. = a * b.

Those. for a given rectangle Spr. = a * b = 70 cm ^ 2.

It is known from the condition that the width of the rectangle is less than the length by 3 cm, which means that b = a + 3 (cm).

We get: a * (a + 3) = 70;

Thus, we can represent the number 70 as the product of two factors 7 and 10:

70 = 7 * 10.

In this case, the multiplier 10 is more than the multiplier 7 by 3, i.e. width a = 7 cm and length b = 10 cm.

Answer: the width of the rectangle is 7 cm, and its length is 10 cm.