The width of the rectangle is 3 times less than the length. Find the area of a rectangle if its perimeter is 56 meters.

Let’s denote by x the width of this rectangle.
According to the condition of the problem, the width of this rectangle is 3 times less than the length, therefore, the length of this rectangle is 3 * x.
It is also known that the perimeter of this rectangle is 56 meters, therefore, we can draw up the following equation:
2 * (3 * x + x) = 56.
We solve the resulting equation:
2 * 4 * x = 56;
8 * x = 56;
x = 56/8;
x = 7 m.
Knowing the width of this rectangle, we find its length:
3 * x = 3 * 7 = 21 m.
Find the area S of a given rectangle as the product of the length and width of a given rectangle:
S = 21 * 7 = 147 m².
Answer: the area of ​​this rectangle is 147 m².