The width of the rectangle is 3 times less than the length of the rectangle. what is the area of the rectangle

The width of the rectangle is 3 times less than the length of the rectangle. what is the area of the rectangle if the perimeter is 136 dm. Explain how it happened.

Let’s denote the width of the rectangle = X dm.

The length of the rectangle = 3 * X dm.

Perimeter (P) is the sum of all sides of the rectangle. There are 4 sides of the rectangle and two of them are equal to the length, the other two are equal to the width, that is:

P = X + X + 3 * X + 3 * X = 2 * (X + 3 * X) = 2 * 4 * X = 8 * X.

By condition, the perimeter = 136 dm, which means:

8 * X = 136 dm;

X = 136/8 = 17 dm.

3 * X = 17 * 3 = 51 dm.

So the width of the rectangle = 17 dm, and the length = 51 dm.

The area of a rectangle is equal to the product of length and width:

17 * 51 = 867 dm2.