The width of the rectangle is 3m 8dm, and the length is 5m 3dm more than the width. Find the perimeter and area of the garden.

First, we find out the length of the specified figure:
3 m 8 dm + 5 m 3 dm = 9 m 1 dm.
We translate the width and length into decimeters:
width – 3 m 8 dm = 3 * 10 + 8 = 38 dm;
length – 9 m 1 dm = 9 * 10 + 1 = 91 dm.
Subtract the perimeter of the figure, remembering that this is the sum of all its sides.
P = 38 dm + 38 dm + 91 dm + 91 dm = 258 decimeters.
Or 38 * 2 + 91 * 2 = 76 + 182 = 258 decimeters.
Now let’s subtract the area by multiplying the length by the width:
S = 38 * 91 = 3458 dm2.
Bottom line: the perimeter is 258 dm2, and its area is 3458 dm2.