The width of the rectangle is 4 times less than the length. The length was increased by 60% and the width was

The width of the rectangle is 4 times less than the length. The length was increased by 60% and the width was decreased by 40%. Has its perimeter decreased or increased, and by what percentage?

1) Let x be the width of the rectangle, then 4x is its length.

2) 4x + (4x: 100 * 60) = 4x + 2.4x = 6.4x – the length of the rectangle increased by 60%.

3) x – (x: 100 * 40) = x – 0.4x = 0.6x – the width of the rectangle, reduced by 40%.

4) Calculate the perimeter of the original rectangle:

4x + x + 4x + x = 10x.

5) Find the perimeter of the rectangle after changing its sides:

6.4x + 0.6x + 6.4x + 0.6x = 14x.

6) Let’s compare the perimeters of the rectangles:

14x> 10x, which means that the perimeter of the rectangle has increased.

7) Find out by what percentage the perimeter has increased:

14x: 10x * 100 = 140% is the perimeter of the resulting rectangle from the perimeter of the original;

140 – 100 = 40% – this is how much the perimeter has increased.

Answer: increased by 40%.