The width of the rectangle is 5 cm and the length is 6 cm more, find the length of the side of the square
The width of the rectangle is 5 cm and the length is 6 cm more, find the length of the side of the square, the perimeter of which is equal to the perimeter of this rectangle.
To solve this problem, recall the formula for the area of a rectangle. The area of the rectangle is equal to the product of the length and the width. S = a * b, where a is the length and b is the width. The perimeter of a rectangle is the sum of the lengths of all its sides. Since in a rectangle the opposite sides are equal, then P = 2 * (a + b), where a is the length, b is the width. Let’s calculate what the length is equal to.
5 + 6 = 11 cm.
Let’s calculate the perimeter of the rectangle.
P = 2 * (11 + 5) = 2 * 16 = 32 cm.
Let’s calculate the side of the square. The perimeter of a square is equal to the sum of the lengths of all its four sides. Since all sides of a square are equal, its perimeter is P = 4a, where a is its side. The area of a square is equal to the square of its side. S = a ^ 2.
a = 32/4 = 8 cm.
S = 8 * 8 = 64 cm ^ 2.
Answer: 64 cm ^ 2.