The width of the rectangle is 5 m, its length is 2 times its width. What is the perimeter of the rectangle? What is its area?

The task:
the width of the rectangle b – 5 m;
the length of the rectangle a -?, 2 times the width;
perimeter P -? m;
area S -? m ^ 2.
Solution:
1) define the length of the rectangle:
a = b 2 = 5 2 = 10 meters;
2) find the perimeter of the rectangle:
P = (a + b) 2 = (10 + 5) 2 = 30 meters
3) calculate the area:
S = a b = 10 5 = 50 square meters.
Answer: S = 50 m ^ 2.