The width of the rectangle is 6 cm less than its length. find the area of a rectangle if its perimeter is 52 cm.

Let’s denote the width of the rectangle as x, then the length is – (6 + x) centimeters. Knowing. that the perimeter is 52 centimeters, we make the equation. The perimeter is the sum of the lengths of all sides of the rectangle.

2 * (x + x + 6) = 52;

2x + 6 = 52/2;

2x + 6 = 26;

2x = 26 – 6;

2x = 20;

x = 20/2;

x = 10.

The width is 10 cm, and the length is 6 + 10 = 16 cm.Let’s find the value of the area of the rectangle.

S = 16 * 10 = 160 cm².

Answer: 160 cm².