The width of the rectangle is 6 cm less than the length. Find the perimeter and area of the rectangle

| April 29, 2021 | education

The width of the rectangle is 6 cm less than the length. Find the perimeter and area of the rectangle if the width is 4/5 of the length.

In order to understand the condition of the problem, you can illustrate it. Depict the length with a segment (5 cells), the width is 4/5 of the length, which means that the length must be divided into 5 equal parts and below, draw a segment consisting of four such parts – this segment will represent the width of the rectangle.

By condition, the width is 6 cm less than the length, which means that the length is 6 cm more than the width, and these 6 cm are one-fifth of the length.

1 – 4/5 = 1/5 (part) of the length is 6 cm.
6 * 5 = 30 (cm) rectangle length.
6 * 4 = 24 (cm) width of the rectangle.
(30 + 24) * 2 = 54 * 2 = 108 (cm) perimeter of the rectangle.
30 * 24 = 720 (cm ^ 2) area of ​​the rectangle.
Answer: 108 cm, 720 cm ^ 2



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