The width of the rectangle is 6cm less than the length. Find the perimeter and area of the rectangle

The width of the rectangle is 6cm less than the length. Find the perimeter and area of the rectangle if the width is 4/5 of the length?

If we denote the value of the length through the variable x, then the width will be equal to 4/5 of the length, that is, 4 / 5x.
The problem says that the difference between length and width is 6 cm, and we determined that the difference between them is 1/5 of x, because 5/5 * x – 4/5 * x = 1/5 * x …
If 1/5 * x = 6, then we find the value of x:
1/5 * x = 6;
1/5 * x * 5 = 6 * 5;
x = 30 (cm).
Find the width value:
30 * 4/5 = 6 * 4 = 24 (cm).
Find the perimeter of the rectangle:
30 * 2 + 24 * 2 = 108 (cm).
Find the area of the rectangle:
30 * 24 = 720 (cm²).
ANSWER: the perimeter is 108 cm, the area is 720 cm².